Area Aptitude Test Paper 3

11) What is the area of a square field whose side is 20 meters?

300 sq. m.
350 sq. m.
400 sq. m.
450 sq. m.

Answer: C

Explanation:

The area of a square = (side) ²
= (20)²
= 400 sq. m.

12) What is the area of a square field whose diagonal is 40 meters?

900 sq. m.
800 sq. m.
750 sq. m.
950 sq. m.

Answer: B

Explanation:

Area of a square = 1/2 (diagonal) 2

= 1/2 (40)²

= 1/2 * 1600

= 800 sq. m.

13) The length of a rectangle is thrice its breath, and its perimeter is 106 meters. What is its area?

507 sq. m.
508 sq. m.
509 sq. m.
510 sq. m.

Answer: A

Explanation:

Let the breath = x

So, the Length = 3x

Perimeter of a rectangle = 2 (Length + Breadth)
                                      So, 2 (3x + x) = 106
                                      6x + 2x = 106
                                      8x = 106
                                      x = 104/8 = 13

Now, Breadth = 13, so, length = 13 * 3 = 39

So, its area = Length * Breadth
= 39 * 13 = 507 sq. m.

14) A rectangular grass field has a length of 85 meters and breadth of 65 meters. It is surrounded by a 5-meter wide path. Find the area of the Path and the cost of constructing it at Rs. 5 per square meter?

4000
6000
8000
7000

Answer: C

Explanation:

Area of the entire grass field including the path = Length (85 + 5 +5) * Breadth (65 + 5+5)
= 95 * 75 = 7125 sq. m.

Area of the grass field excluding the path = 85 * 65 = 5525 sq. m.

So, area of the path = 7125 - 5525 = 1600 sq. m.

The cost of constructing is Rs. 5 per square meter.

So, the cost of constructing the entire path = 1600 * 5 = Rs. 8000

15) If the area of the trapezium, whose parallel sides are 6 cm and 10 cm is 32 sq. cm, what will be the distance between the parallel sides?

2 cm
4 cm
5 cm
8 cm

Answer: B

Explanation:

Parallel sides of a trapezium = 6 cm, and 10 cm
Area of trapezium = Area Aptitude ( sum of the parallel sides ) × distance between the parallel sides
32= ( 6+10 ) × distance