Java Float compare() method

The compare() method of Java Float class compares the two specified float values i.e. f1 and f2.

Syntax:

Parameters:

The parameters passed are f1(the first float value) and f2(the second float value).

Return Value:

This method returns the integer value of the argument.

Returns a zero if value of f1 is same as value of f2(f1 = f2).
Return a positive value if f1 is greater than f2(f1 > f2).
Return a negative value if f1 is less than f2(f1

Example 1

import java.lang.Float;


public class FloatcompareMethodExample1 {

    public static void main(String[] args) {


        Float f1 = new Float("10");
        Float f2 = new Float("50.44");

        // comparing f1 and f2
        int compare=Float.compare(f1 , f2);

        if(compare > 0){

            System.out.println(f1+" is greater and "+f2+" is smaller.");
        }

        else if(compare<0){

            System.out.println(f1+" is smaller "+f2+" is greater.");
        }
        else{

            System.out.println(" Both are equal! ");
        }
    }
}

Test it Now

Output:

10.0 is smaller 50.44 is greater.

Example 2

import java.lang.Float;

public class FloatcompareMethodExample2 {

    public static void main(String[] args) {

        Float f1 = new Float("10");

        // comparing f1 and f2
        int compare=Float.compare(f1 );

        if(compare > 0){

            System.out.println(f1+" is greater .");
        }

        else if(compare<0){

            System.out.println(f1+" is smaller .");
        }
        else{

            System.out.println(" Both are equal! ");
        }
    }
}

Test it Now

Output:

Error:(13, 26) java: method compare in class java.lang.Float cannot be applied to given types;
  required: float,float
  found: java.lang.Float
  reason: actual and formal argument lists differ in length

It is compulsory to pass two arguments in Float class compare() method otherwise, it will give you an error.

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