Java Integer highestOneBit() Method

The highestOneBit() method is a method of Integer class under java.lang package. This method returns int value with at most a single one-bit, in the position of the highest-order ("leftmost") one-bit in the specified int value. If the specified value has no one-bits or is equal to zero in its two's complement binary representation, it returns zero.

Syntax:

Following is the declaration of highestOneBit() method:

Parameter:

DataType	Parameter	Description	Required/Optional
int	i	It accepts integer type parameter whose highest order bit integer value is to be returned.	Required

Returns:

The highestOneBit() method returns an int value with a single one-bit, in the position of the highest-order one-bit in the specified value, or zero if the specified value is itself equal to zero.

Exceptions:

Compatibility Version:

Java 1.5 and above

Example 1

public class IntegerHighestOneBitExample1 {
	public static void main(String[] args) {
		System.out.println("Integer value in the position of the highest-order one-bit: "+Integer.highestOneBit(20));
    }
}

Test it Now

Output:

Integer value in the position of the highest-order one-bit: 16

Example 2

import java.util.Scanner;
public class IntegerHighestOneBitExample2 {
	public static void main(String[] args) {
		//Input value from console
		System.out.print("Enter the desired value: ");
		Scanner readInput = new Scanner(System.in);
		Integer i = readInput.nextInt();
		readInput.close();
		System.out.println("Integer value in the position of the highest-order one-bit: "+Integer.highestOneBit(i));
    }
}

Output:

Enter the desired value: 15
Integer value in the position of the highest-order one-bit: 8

Example 3

public class IntegerHighestOneBitExample3 {
	public static void main(String[] args) {
	  int num = 25;
        System.out.print("Input Number is: " + num);
        // returns an int value with at most a single one-bit, in the position
        // of the highest-order or the leftmost one-bit in the specified int value
        System.out.print("\nHighest 1-bit of the given integer is: "+Integer.highestOneBit(num));       
        int a = -20;
        System.out.println("\n\nInput Number is = " + a);
        System.out.print("Highest one bit of the given integer is = "+Integer.highestOneBit(a));
        
    }
}

Test it Now

Output:

Input Number is: 25
Highest 1-bit of the given integer is: 16

Input Number is = -20
Highest one bit of the given integer is = -2147483648

Example 4

public class IntegerHighestOneBitExample4 {
	public static void main(String[] args) {				
	    int i = 114;
	    System.out.print("Input Number: " + i);
	    // returns Binary Equivalent
	    System.out.print("\nBinary Equivalent: " + Integer.toBinaryString(i));
	    // returns the number of one-bits 
	    System.out.print("\nTotal Number of 1-bits: " + Integer.bitCount(i));
	    // returns an int value of the highest-order ("leftmost") one-bit  
	    System.out.print("\nInteger Value of Highest 1-bit: " + Integer.highestOneBit(i));    
        }
}

Test it Now

Output:

Input Number: 114
Binary Equivalent: 1110010
Total Number of 1-bits: 4
Integer Value of Highest 1-bit: 64

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Java Integer highestOneBit() Method

Syntax:

Parameter:

Returns:

Exceptions:

Compatibility Version:

Example 1

Example 2

Example 3

Example 4

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