Java Random nextFloat() Method

The nextFloat() method of Random class returns the next pseudorandom, uniformly distributed float value between 0.0 and 1.0 from the random number generator's sequence.

Syntax

Parameters

Return Value

The nextFloat() method returns the next pseudorandom float number between 0.0 and 1.0.

Example 1

import java.util.Random;

public class JavaRandomNextFloatExample1 {
public static void main(String[] args) {
        Random random = new Random();
//return the next pseudorandom float value
Float val = random.nextFloat();
System.out.println("Random Float value : "+val);
        Float val1 = random.nextFloat();
System.out.println("Random Float value : "+val1);
    }
}

Output:

Random Float value : 0.25081772
Random Float value : 0.52181274

Example 2

import java.util.Random;
import java.util.Scanner;
import java.util.concurrent.ArrayBlockingQueue;

public class JavaRandomNextFloatExample2 {
static  int j=1;
public static void main(String[] args) {
        Scanner scanner = new Scanner(System.in);
System.out.print("Enter number of students.");
int capacity = scanner.nextInt();
ArrayBlockingQueue<String> queue = new ArrayBlockingQueue<String>(capacity);
System.out.println("Enter name of "+capacity+" students.");
for (int i=0;i<capacity;i++){
System.out.print(j++ +" ");String str = scanner.next();
queue.add(str);
        }
j=1;
        Random random = new Random();
for (String xyz :queue) {
            Float val = random.nextFloat();
System.out.println(j+++". " +xyz+"'s id  : "+val);
        }
    }
}

Output:

Enter number of students.5
Enter name of 5 students.
1 Payal
2 Anshu
3 Baby
4 Mona
5 Jugnoo
1. Payal's id  : 0.14586294
2. Anshu's id  : 0.78586906
3. Baby's id  : 0.76507455
4. Mona's id  : 0.9362442
5. Jugnoo's id  : 0.5890219

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