Java Short compare() Method

The compare() method of Java Short class compares two Short object numerically. Short is wrapper class.

Syntax

Parameters

X: first short value

Y: second short value

Return value

Return 0, if first short value is equal to second short value (x=y).
Return less than 0, if first short value less than to second short value (x
Return more than 0, if first short value greater than to second short value (x>y).

Example 1

when "short x = short y"

public class ShortCompareExample1 { 
public static void main(String[] args) {     
short x=30, y=30; // when x=y       
Short sValue1 = new Short(x);        
Short sValue2 = new Short(y);         //comparing two shot values        
int compareValue=Short.compare(sValue1, sValue2);                 
System.out.println(" Two short values compared result: " + compareValue);           
 }

Test it Now

Output:

Two short values compared result: 0

Example 2

when ?short x < short y?       
public class ShortCompareExample2 { 
 public static void main(String[] args) {     
short x=30, y=40; // when x<y             
Short sValue1 = new Short(x);        
Short sValue2 = new Short(y);         //comparing two shot values        
int compareValue=Short.compare(sValue1, sValue2);                 
System.out.println(" Two short values compared result: " + compareValue);            
} 
} 

Test it Now

Output:

Two short values compared result: -10

Example 3

when ?short x > short y?    
public class ShortCompareExample3 { 
public static void main(String[] args) {     
short x=50, y=40; // when x>y             
Short sValue1 = new Short(x);        
Short sValue2 = new Short(y);         //comparing two shot values        
int compareValue=Short.compare(sValue1, sValue2);                 
System.out.println(" Two short values compared result: " + compareValue);            
}
} 

Test it Now

Output: