Java System exit() Method

The exit() method of System class terminates the current Java virtual machine running on system. This method takes status code as an argument.

Status - exit(0) - indicates Successful termination
Status - exit(-1) - indicates unsuccessful termination with Exception
Status - exit(1) - indicates Unsuccessful termination

Syntax

Parameter

status - It is the exit status.

Returns

This method does not return any value.

Exception

If security manager exist and his checkexit method doesn't approve exit with specified status then a SecurityException is thorwn.

Example 1

import java.lang.*;
public class SystemExitExample1 {

	public static void main(String[] args) {
		int a[]= {9,8,7,6,5,4,3,2,1};
		for(int i=0;i<a.length;i++)
		{
			if(a[i]>5)
			{
			System.out.println("array["+i+"]="+a[i]);
			}
			else
			{
				System.out.println("terminating jvm,exiting");
				System.exit(0);//Treminatejvm
			}
		}
	}
}

Output:

array[0]=9
array[1]=8
array[2]=7
array[3]=6
terminatingjvm,exiting

Example 2

public class SystemExitExample2 {

	public static void main(String[] args) {
		System.out.println("program will terminate when i is 1");
for(int i=10;i>0;i--)    {       
System.out.println("your no is "+i);
if(i==1){
System.out.println("Value is 1 now terminating your program");
System.exit(1); //exit program
            }
            }
	}
}

Output:

program will terminate when i is 1
your no is 10
your no is 9
your no is 8
your no is 7
your no is 6
your no is 5
your no is 4
your no is 3
your no is 2
your no is 1
Value is 1 now terminating your program

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