RESTful JAX-RS File Upload Example

Like download in previous page, we can easily upload a file such as image file, pdf file, excel file, text file etc.

The @FormDataParam("file") annotation is used to mention file parameter in the service class. The @Consumes(MediaType.MULTIPART_FORM_DATA) is used to provide information of the file upload.

To upload file using JAX-RS API, we are using jersey implementation.

Click me to download jersey jar files.

To upload file through jersey implementation, you need to provide extra configuration entry in web.xml file.

    <init-param>
    <param-name>jersey.config.server.provider.classnames</param-name>
    <param-value>org.glassfish.jersey.filter.LoggingFilter;
     org.glassfish.jersey.media.multipart.MultiPartFeature</param-value>
</init-param>

Let's see the complete code to upload file using RESTful JAX-RS API.

JAX-RS File Upload

File: FileUploadService.java

package com.javatpoint.rest;
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import javax.ws.rs.Consumes;
import javax.ws.rs.POST;
import javax.ws.rs.Path;
import javax.ws.rs.core.MediaType;
import javax.ws.rs.core.Response;
import org.glassfish.jersey.media.multipart.FormDataContentDisposition;
import org.glassfish.jersey.media.multipart.FormDataParam;
@Path("/files")
public class FileUploadService {
 	@POST
	@Path("/upload")
	@Consumes(MediaType.MULTIPART_FORM_DATA)
 	public Response uploadFile(
 			@FormDataParam("file") InputStream uploadedInputStream,
 			@FormDataParam("file") FormDataContentDisposition fileDetail) {
  			String fileLocation = "e://" + fileDetail.getFileName();
 	                //saving file
 			try {
 				FileOutputStream out = new FileOutputStream(new File(fileLocation));
 				int read = 0;
 				byte[] bytes = new byte[1024];
 				out = new FileOutputStream(new File(fileLocation));
 				while ((read = uploadedInputStream.read(bytes)) != -1) {
 					out.write(bytes, 0, read);
 				}
 				out.flush();
 				out.close();
 			} catch (IOException e) {e.printStackTrace();}
 			String output = "File successfully uploaded to : " + fileLocation;
  			return Response.status(200).entity(output).build();
  		}
  }

File: web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee 
http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
 <servlet>
    <servlet-name>Jersey REST Service</servlet-name>
    <servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
     <init-param>
        <param-name>jersey.config.server.provider.packages</param-name>
        <param-value>com.javatpoint.rest</param-value>
    </init-param>
    <init-param>
    <param-name>jersey.config.server.provider.classnames</param-name>
    <param-value>org.glassfish.jersey.filter.LoggingFilter;
     org.glassfish.jersey.media.multipart.MultiPartFeature</param-value>
</init-param>
    <load-on-startup>1</load-on-startup>
  </servlet>
  <servlet-mapping>
    <servlet-name>Jersey REST Service</servlet-name>
    <url-pattern>/rest/*</url-pattern>
  </servlet-mapping>
</web-app> 

File: index.html

<h2>File Upload Example</h2>
<form action="rest/files/upload" method="post" enctype="multipart/form-data">
	   <p>
		Select a file : <input type="file" name="file" size="45" />
	   </p>
	   <input type="submit" value="Upload File" />
</form>

Now run this application on server, you will see the following output:

Output:

Click me to download this example

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