Java Byte compareTo() method

The compareTo() method of Java Byte class compares two Byte objects numerically

Syntax:

Parameters:

The parameter 'anotherByte' represents the Byte to be compared.

Specified by

This method is specified by compareTo in interface Comparable<Byte>

Return Value

This method returns an integer value.

It returns zero, if this Byte is equal to the parameter.
It returns positive one, if this Byte is numerically greater than the argument Byte.
It returns negative one, if this Byte is numerically smaller than the argument Byte.

Example 1

public class JavaByteCompareToExample1 {
    public static void main(String[] args) {
        Byte byte1=127;
        Byte byte2=67;
        //It compares two Byte objects numerically
        int val=byte1.compareTo(byte2);
        if(val==0){
            System.out.println(byte1+" and "+byte2+" values are equal.");
        }
        else if(val>0){
            System.out.println(byte1+" is greater than "+byte2+" .");
        }
        else{
            System.out.println(byte2+" is greater than "+byte1+" .");
        }
    }
}

Test it Now

Output:

127 is greater than 67 .

Example 2

import java.util.Scanner;
public class JavaByteCompareToExample2 {
    public static void main(String[] args) {
        Byte byte1=18;
        Scanner scanner=new Scanner(System.in);
        System.out.print("Enter your age : ");
        byte byte2=scanner.nextByte();
        int val=byte1.compareTo(byte2);
        if (val<0){
            System.out.println("Congratulations! You are an adult. Now you can vote.");
        }
        else {
            int byte3=byte1-byte2;
            System.out.println("Oops! You are not an adult. You can vote after "+ byte3+" years.");
        }
    }
}

Output:

Enter your age : 24
Congratulations! You are an adult. Now you can vote.

Example 3

public class JavaByteCompareToExample3 {
    public static void main(String[] args) {
        //byte value should be in the range between -127 to 128
        Byte b1= 567;
        byte b2=Byte.MIN_VALUE;
        int val=b1.compareTo(b1);
        if(val>0){
            System.out.println(b1+" is greater than "+b2);
        }
        else{
            System.out.println(b2+" is greater than "+b1);
        }
    }
}

Test it Now

Output:

Error:(5, 18) java: incompatible types: int cannot be converted to java.lang.Byte

Next TopicJava Byte

← prev next →

For Videos Join Our Youtube Channel: Join Now

Feedback

Send your Feedback to [email protected]

Help Others, Please Share

Learn Latest Tutorials

Splunk

SPSS

Swagger

Transact-SQL

Tumblr

ReactJS

Regex

Reinforcement Learning

R Programming

RxJS

React Native

Python Design Patterns

Python Pillow

Python Turtle

Keras

Preparation

Aptitude

Reasoning

Verbal Ability

Interview Questions

Company Questions

Trending Technologies

Artificial Intelligence

AWS

Selenium

Cloud Computing

Hadoop

ReactJS

Data Science

Angular 7

Blockchain

Git

Machine Learning

DevOps

B.Tech / MCA

DBMS

Data Structures

DAA

Operating System

Computer Network

Compiler Design

Computer Organization

Discrete Mathematics

Ethical Hacking

Computer Graphics

Software Engineering

Web Technology

Cyber Security

Automata

C Programming

C++

Java

.Net

Python

Programs

Control System

Data Mining

Data Warehouse

^{Like/Subscribe us for latest updates or newsletter}

Java Byte Class

Java Byte compareTo() method

Syntax:

Parameters:

Specified by

Return Value

Example 1

Example 2

Example 3

Feedback

Help Others, Please Share

Learn Latest Tutorials

Preparation

Trending Technologies

B.Tech / MCA